w2cDrv.Device.Info.WaveOutDrvID = 4294967294

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   On Windows 2003 running latest 32-bit drivers, I get the following:w2cDrv.Device.Info.WaveOutDrvID of 4294967294 (hex FFFFFFFE).  This value
is typically 0.  It is zero when I run this same application on my local
Windows XP system.  Thererfore, get an exception attempting to play a wave file using: w2cDrv.Device.Audio.PlayWaveFile(filename, 0,
cint(w2cDrv.Device.Info.WaveOutDrvID)).  The WaveOutDrvId parameter for Audio.PlayWaveFile is an unsigned integer and causes an arithmetic overflow exception since the 4294967294 it too large.
Thanks for any help on this issue.

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hcripps Members Profile Send Private Message Find Members Posts Add to Buddy List Newbie Joined: Jan 07 2011 Status: Offline Points: 2	Post Options Post Reply Quote hcripps Report Post Thanks(0) Quote Reply Topic: w2cDrv.Device.Info.WaveOutDrvID = 4294967294 Posted: Jan 12 2011 at 11:37am
	On Windows 2003 running latest 32-bit drivers, I get the following: w2cDrv.Device.Info.WaveOutDrvID of 4294967294 (hex FFFFFFFE). This value is typically 0. It is zero when I run this same application on my local Windows XP system. Thererfore, get an exception attempting to play a wave file using: w2cDrv.Device.Audio.PlayWaveFile(filename, 0, cint(w2cDrv.Device.Info.WaveOutDrvID)). The WaveOutDrvId parameter for Audio.PlayWaveFile is an unsigned integer and causes an arithmetic overflow exception since the 4294967294 it too large. Thanks for any help on this issue.